3x^2-5x=-3x^2=6

Solution for 3x^2-5x=-3x^2=6 equation:

3x^2-5x=-3x^2=6

We move all terms to the left:

3x^2-5x-(-3x^2)=0

We get rid of parentheses

3x^2+3x^2-5x=0

We add all the numbers together, and all the variables

6x^2-5x=0

a = 6; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·6·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*6}=\frac{10}{12}
=5/6
$